Question 1137292: The length of garden was 3 feet less than 4 times its width. This year, Jeff decided to make the length 6 feet longer than triple the width .How much additions will he add to his garden? Write the answer in factored form.
Found 3 solutions by josgarithmetic, ikleyn, MathTherapy:
Answer by josgarithmetic(39630)   (Show Source):
Answer by ikleyn(52921)  (Show Source):
You can put this solution on YOUR website! .
Since the calculations and the answer " x*(9-2x) " in the post by @josgarithmetic are incorrect,
I came to bring the correct solution.
Last year dimensions, 4x-3 and x
This year dimensions, 3x+6 and x
The additional area is
x(3x+6)-x(4x-3) = x(3x+6-4x+3) = x(-x+9) = x(9-x). ANSWER
It is really an addition if x < 9 feet.
If x > 9 feet, it is not an addition.
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My solution assumes that the width of the park was with no change, in other words, the width next year remained the same as
in the year before, although the problem is silent about it.
Answer by MathTherapy(10557)  (Show Source):
You can put this solution on YOUR website!
The length of garden was 3 feet less than 4 times its width. This year, Jeff decided to make the length 6 feet longer than triple the width .How much additions will he add to his garden? Write the answer in factored form.
The answer, x(9 - 2x) from the other person is WRONG, AS USUAL.
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