SOLUTION: Ship A, sailing due east at 8 km/h, sights ship B 5 km to the southeast when ship B is sailing due north at 6 km/h. How close to each other will the two ships be when they pass?
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Question 1137158: Ship A, sailing due east at 8 km/h, sights ship B 5 km to the southeast when ship B is sailing due north at 6 km/h. How close to each other will the two ships be when they pass? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Ship A, sailing due east at 8 km/h, sights ship B 5 km to the southeast when ship B is sailing due north at 6 km/h.
How close to each other will the two ships be when they pass?
:
The relationship of the two ships is such that their paths will form a right triangle with equal sides.
:
let t = time when ship A will be exactly due north of B, this is the their closest point
For the moment let's assume they are going the same speed, 8 km/h
Solving the right triangle
(8t)^2 + (8t^2) = 5^2
64t^2 + 64t^2 = 25
128t^2 = 25
t =
t = .442 hrs is the time when ship A will exactly north of ship B
distance traveled .442 * 8 = 3.5355 km
During this time ship B will travel .442 * 6 = 2.652 km
therefore
3.355 - 2.652 = .8835 km will be the distance between them, the minimum
