SOLUTION: A small heating unit takes 40 h longer to melt a piece of iron than does a larger unit. Working together, the heating units can melt the iron in 15 h. How long would it take each h
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Question 1137144: A small heating unit takes 40 h longer to melt a piece of iron than does a larger unit. Working together, the heating units can melt the iron in 15 h. How long would it take each heating unit, working alone, to melt the iron?
You can put this solution on YOUR website! Let = time in hrs for the larger unit = time in hrs for the smaller unit
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Add their rates of melting to get their rate melting together
Multiply both sides by ( can't use negative result )
and
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Larger unit takes 20 hrs
Smaller unit takes 60 hrs
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check:
OK
You can put this solution on YOUR website! Rate larger unit takes to melt iron: 1/x per hour
Rate smaller unit takes to melt iron: 1/(x+40) per hour
Rate of both working together: 1/x + 1/(x+40) = 1/15 per hour
Solve for x:
x = 20 and x = -30
Since the rate cannot be a negative number, we can ignore x = -30. So, the final answer is x = 20.
Rate larger unit takes to melt iron: 1/x per hour = 1/20 per hour
Rate smaller unit takes to melt iron: 1/(x+40) per hour = 1/60 per hour
So, working alone, the larger unit takes 20 hours to melt the iron and the smaller unit takes 60 hours.