Question 1137025: Person A can paint the neighbors house 2 times as fast as person B. The year A and B worked together, it took them 2 days. how long would it take each to paint the house?
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52794)   (Show Source):
You can put this solution on YOUR website! .
Painter A works as effectively, as two painters B.
So, you can reformulate the problem in this way, saying that THREE painters B complete the painting job in 2 days.
It means that one painter B, working alone, will make the entire job in 2*3 = 6 days.
Hence, painter A, who works 2 times as fast as B, will complete the job in 3 days.
ANSWER. Painter A - 3 days; painter B - 6 days.
Solved // mentally (without using equations).
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It is a standard and typical joint work problem.
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Answer by greenestamps(13200)  (Show Source):
You can put this solution on YOUR website!
The response from tutor @ikleyn shows one good way of solving the problem using logical reasoning and some simple arithmetic.
Here is another similar way to solve the problem.
Since A works twice as fast as B, when they work together A does 2/3 of the job.
Then, since together the two of them take 2 days to paint the house, the time required by A alone would be 2*(3/2) = 3 days.
And so then the time required by B alone would be twice that, or 6 days.
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