SOLUTION: A ball is thrown vertically upward with an initial velocity of 80 feet per second. The distance in feet of the ball from the ground after t second is s(t)= 80t-16t^2
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-> SOLUTION: A ball is thrown vertically upward with an initial velocity of 80 feet per second. The distance in feet of the ball from the ground after t second is s(t)= 80t-16t^2
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Question 1136993: A ball is thrown vertically upward with an initial velocity of 80 feet per second. The distance in feet of the ball from the ground after t second is s(t)= 80t-16t^2 Found 2 solutions by Alan3354, ikleyn:Answer by Alan3354(69443) (Show Source):
