SOLUTION: The length of a rectangular field is 15 Yards less than triple the width. If the perimeter of the field is 346 yards, what are the fields dimensions?

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Question 1136935: The length of a rectangular field is 15 Yards less than triple the width. If the perimeter of the field is 346 yards, what are the fields dimensions?
Found 2 solutions by josgarithmetic, addingup:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
length, 3w-15
width, w

%283w-15%29%2Bw=346%2F2
.
.

Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
2L + 2W = 346
L = 3W - 15 substitute in the equation above
2(3W - 15) + 2W = 346
6W - 30 + 2W = 346
8W = 376
W = 47
L = 3W - 15
L = 3(47) - 15
L = 126
Check:
2L + 2W = 346
2(126) + 2(47) = 346 Correct