SOLUTION: I have now have 12 M&Ms, all of varying colors. Suppose I want to select 3 M&Ms from these 12 to decorate a homemade necklace. How many different color orderings are there if I am
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Question 1136925: I have now have 12 M&Ms, all of varying colors. Suppose I want to select 3 M&Ms from these 12 to decorate a homemade necklace. How many different color orderings are there if I am selecting 3 M&Ms and the order of the M&Ms that I am selecting matter? Answer by greenestamps(13200) (Show Source):
Since order matters, you have 12 choices for the first, then 11 choices for the second, then 10 choices for the third. The total number of ordered selections of 3 of the 12 M&Ms is 12*11*10 = 1320.