SOLUTION: The waiting time until a customer is served at a fast food restaurant during lunch hours has a skewed distribution with a mean of 2.5 minutes and a standard deviation of 0.4 minute
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Question 1136855: The waiting time until a customer is served at a fast food restaurant during lunch hours has a skewed distribution with a mean of 2.5 minutes and a standard deviation of 0.4 minute. Suppose that a random sample of 47 waiting times will be taken. Compute the probability that the mean waiting time for the sample will be longer than 2.6 minutes. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! t=(x bar-mean)/s/sqrt(n)
t>(2.6-2.5)/0.4/sqrt(47)
t>0.1*sqrt(47)/0.4
t>1.71
for df=46, that probability is about 0.095