|
Question 1136802: Please help me graph the line that satisfies each condition:
1. slope=-1, contains P(-2, 1)
2. contains Q(-1, 3) and is perpendicular to line AB with A(-2, 0) and B(4, 3)
3. contains M(1, -1) and is parallel to line FG with F(3, 5) and G(-3, -1)
4. slope=-3/4, contains K(3, -2)
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! 1. slope=-1, contains P(-2, 1)
----
m = slope
Use y-y1 = m*(x-x1) where (x1,y1) is the point.
===================
2. contains Q(-1,3) and is perpendicular to line AB with A(-2,0) and B(4,3)
Find the slope, m1, of AB
The slope of lines perpendicular, m2, is -1/m1
The it's the same as #1
========================
3. contains M(1,-1) and is parallel to line FG with F(3,5) and G(-3,-1)
---
Find the slope, m, of FG.
The slopes of parallel lines are the same.
etc.
======================
4. slope=-3/4, contains K(3,-2)
y-y1 = m*(x-x1)
*********************************************************
That gives you the equation of each line.
they're straight lines, so you need 2 points for a graph.
Answer by ikleyn(52810)  (Show Source):
|
|
|
| |
