SOLUTION: The equation 4x^4-5x^3-1x^2=0 has three solutions A b and c where A<B<C Find A and B and C?

Algebra ->  Trigonometry-basics -> SOLUTION: The equation 4x^4-5x^3-1x^2=0 has three solutions A b and c where A<B<C Find A and B and C?      Log On


   

Question 1136756: The equation 4x^4-5x^3-1x^2=0 has three solutions A b and c where A Find A and B and C?
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
4x^4-5x^3-1x^2=0
factor an x^2 out
x^2(4x^2-5x-1)=0
x^2=0, x=0
x=(1/8)(5+/- sqrt (25+16))
x=(1/8)(5+/-sqrt(41))
numerical solution is +1.425 and -0.175 The third solution is 0.
graph%28300%2C300%2C-2%2C2%2C-10%2C10%2C4x%5E4-5x%5E3-x%5E2%29