SOLUTION: What are the zeros and the multiplicity of the polynomial below? f (x) = x^3 + 2x^2 − 9x − 18

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Question 1136673: What are the zeros and the multiplicity of the polynomial below?
f (x) = x^3 + 2x^2 − 9x − 18

Answer by ikleyn(52847) About Me  (Show Source):
You can put this solution on YOUR website!
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  x^3 + 2x^2 − 9x − 18 = apply grouping and factoring = (x^3 - 9x) + (2x^2 - 18) = x*(x^2 - 9) + 2*(x^2 - 9) = 


= (x+2)*(x^2-9) = (x+2)*(x+3)*(x-3).


The zeroes are -3, -2 and 3, each of multiplicity 1.

Solved.