SOLUTION: An airplane encountered a head wind during a flight between Joppetown and Jawsburgh, which took 4 hours and 42 minutes. The return flight took 4 hours. If the distance from Joppeto

Let u be the airspeed of the airplane (in miles per hour), and

let v be the speed of the wind.



The speed of the airplane flying with the wind is (u + v); at the same time it is equal to  

     = 350 miles per hour.

So, your first equation is

    u + v = 350.      (1)



The speed of the airplane flying againt the same wind is (u - v); at the same time it is equal to  

     =  =  =  miles per hour.

So, your second equation is

    u - v = .    (2)



Add equations (1) and (2). You will get


    2u =  =  = 647.872  =====>  u =  = 323.936 miles per hour.


Substitute this value of "u" into the equation (2) to get v = 350-u = 26.064.


ANSWER.  The airspeed of the plane is  323.936 miles per hour;  the speed of the wind is  26.064 miles per hour.