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a + b + c + d + e = 21 (1)
a + b = 6 (2)
b + c = 10 (3)
c + d = 7 (4)
d + e = 9 (5)
1. From equations (2) and (5), substitute a + b = 6 and d + e = 9 into equation (1). You will get
6 + c + 9 = 21, which implies c = 21 - 6 - 9 = 6.
2. Now equation (3) becomes b + 6 = 10, giving b = 10 - 6 = 4,
while equation (4) becomes 6 + d = 7, giving d = 7 - 6 = 1.
3. Now equation (2) becomes a + 4 = 6, giving a = 6 - 4 = 2,
while equation (5) becomes 1 + e = 9, giving e = 9 - 1 = 8.
Answer. a= 2, b= 4, c= 6, d= 1 and e= 8.
Solved.