SOLUTION: What is the degree and the leading coefficient for x^2 (2x − 3)^2?
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Question 1136627
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What is the degree and the leading coefficient for x^2 (2x − 3)^2?
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Theo(13342)
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i believe the degree is 4 and the leading coefficient is 4.
if you multiply the factors out, you get:
x^2 * (2x - 3) * (2x - 3) becomes:
(2x^3 - 3x^2) * (2x - 3) which becomes:
4x^4 - 6x^3 - 6x^3 + 9x^2 which simplifies to:
4x^4 - 12x^3 + 9x^2.
since this is already arranged in descending order of degree, then:
the degree is 4 and the leading coefficient is 4.
the original equation is y = x^2 * (2x-3)^2.
the final equation is y = x^4 - 12x^3 + 9x^2.
these two equations are equivalent to each other.
if you graph them both, they will generate the identical curve, as shown below: