SOLUTION: You bike 35 miles from A to B (due south) and then walk 12 miles from B to C at a bearing of N 35 E. To go back to A (from C) you catch a ride and your bearing is N 40 W. what is
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-> SOLUTION: You bike 35 miles from A to B (due south) and then walk 12 miles from B to C at a bearing of N 35 E. To go back to A (from C) you catch a ride and your bearing is N 40 W. what is
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Question 1136456: You bike 35 miles from A to B (due south) and then walk 12 miles from B to C at a bearing of N 35 E. To go back to A (from C) you catch a ride and your bearing is N 40 W. what is the total distance you traveled (bike + walk + ride).
You can put this solution on YOUR website! You bike 35 miles from A to B (due south) and then walk 12 miles from B to C at a bearing of N 35 E.
To go back to A (from C) you catch a ride and your bearing is N 40 W.
what is the total distance you traveled (bike + walk + ride).
:
Draw this out and we have, (do we really need to know the bearing of C to A?)
a = 12 mi
B = 35 degrees
b = dist from C to A, riding in the car
c = 35 mi
:
Use the law of cosines
b^2 = a^2 + c^2 - 2(ac)*cos(B)
b^2 = 12^2 + 35^2 - 2(12*35)*cos(35)
b^2 = 144 + 1225 -2(420)*.819
b^2 = 1369 - 688.09
b^2 = 680.91
b =
b = 26.09 mi from C to A, riding
:
Total dist traveled 35 + 12 + 26.09 = 73.09 mi
