SOLUTION: Problem Page Working together, two pumps can drain a certain pool in 3 hours. If it takes the older pump 13 hours to drain the pool by itself, how long will it take the newer pump

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Problem Page Working together, two pumps can drain a certain pool in 3 hours. If it takes the older pump 13 hours to drain the pool by itself, how long will it take the newer pump      Log On


   

Question 1136385: Problem Page
Working together, two pumps can drain a certain pool in 3 hours. If it takes the older pump 13 hours to drain the pool by itself, how long will it take the newer pump to drain the pool on its own?
Answer by ikleyn(52809) About Me  (Show Source):
You can put this solution on YOUR website!
.
Working together, two pumps fill  1%2F3  of the pool per hour.


Older pump fills  1%2F13  of the pool per hour.


Hence, new pump  fills  1%2F3+-+1%2F13 = 13%2F39+-+3%2F39 = 10%2F39  of the pool per hour.


It means that this pump requires  39%2F10 hours = 3.9 hours = 3 hours and 54 minutes to fill the pool working alone.

Solved.

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It is a standard and typical joint work problem.

There is a wide variety of similar solved joint-work problems with detailed explanations in this site.  See the lessons
    - Using Fractions to solve word problems on joint work
    - Solving more complicated word problems on joint work
    - Selected joint-work word problems from the archive


Read them and get be trained in solving joint-work problems.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic
"Rate of work and joint work problems"  of the section  "Word problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.