SOLUTION: Use the vertex (h, k) and a point on the graph (x, y) to find the general form of the equation of the quadratic function. (h, k) = (−3, −1), (x, y) = (−5, 3) * can some

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Use the vertex (h, k) and a point on the graph (x, y) to find the general form of the equation of the quadratic function. (h, k) = (−3, −1), (x, y) = (−5, 3) * can some      Log On


   

Question 1136384: Use the vertex (h, k) and a point on the graph (x, y) to find the general form of the equation of the quadratic function.
(h, k) = (−3, −1), (x, y) = (−5, 3)
* can someone help? So far I’ve gotten 1/4(x+3)^2-1, but it is incorrect. I’ve plugged the given numbers into their respective places in the formula, y=a(x-h)^2+k, but am lost where I’m going wrong. Thank you.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

(h, k) = (-3, -1), (x,+y) = (-5, 3)
y=a%28x-h%29%5E2%2Bk...given h=-3,k=-1.x=-5,y=3; plug it all in and calculate a
3=a%28-5-%28-3%29%29%5E2%2B%28-1%29
3=a%28-5%2B3%29%5E2-1
3%2B1=a%28-2%29%5E2
4=a%2A4
a=1
your equation is: y=%28x%2B3%29%5E2-1