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| Question 1136360:  In parallelogram ABCD, E is the midpoint of
 AB
 and F is the midpoint of
 DC
 . Let G be the intersection of the diagonal
 DB
 and the line segment
 EF
 . Prove that G is the midpoint of
 EF.
 △EGB = △
 by reason
 Answer by greenestamps(13209)
      (Show Source): 
You can put this solution on YOUR website! 
 AE, BE, CF, and DF are all congruent because they are each half of sides AB and CD, which are congruent because they are opposite sides of a parallelogram.
 
 In triangles EGB and FGD, all three corresponding pairs of angles are congruent.
 
 Then with sides BE and DF congruent, triangles EGB and FGD are congruent, making EG congruent to GF; and that makes G the midpoint of EF.
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