SOLUTION: Find an equation of a line perpendicular to the given line that contains the given point. Write the equation in slope-intercept form. (If the equation is a vertical line, use the f
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-> SOLUTION: Find an equation of a line perpendicular to the given line that contains the given point. Write the equation in slope-intercept form. (If the equation is a vertical line, use the f
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Question 1136195: Find an equation of a line perpendicular to the given line that contains the given point. Write the equation in slope-intercept form. (If the equation is a vertical line, use the form x = a.)
line
5x − 4y = 6,
point
(−4, 3)
Any line perpendicular to the given line 5x - 4y = 6 has an equation
5y + 4x = c, (1)
where "c" is a constant term.
Since a line (1) should contain the point (-4,3), equation (1) must be true when you substitute
the coordinates of the point x= -4 and y= 3 into the equation.
By doing it, you determine the value of "c"
5*3 + 4*(-4) = c = 15 - 16 = -1.
Therefore, your equation (1) takes the form
5y + 4x = -1.
In the slope-intercept form, it is
y = .
It is your final answer
Plot y = 5x - 4y = 6 (red) and y = (green)
Solved.
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