SOLUTION: Find an equation of a line perpendicular to the given line that contains the given point. Write the equation in slope-intercept form. (If the equation is a vertical line, use the f

Algebra ->  College  -> Linear Algebra -> SOLUTION: Find an equation of a line perpendicular to the given line that contains the given point. Write the equation in slope-intercept form. (If the equation is a vertical line, use the f      Log On


   



Question 1136195: Find an equation of a line perpendicular to the given line that contains the given point. Write the equation in slope-intercept form. (If the equation is a vertical line, use the form x = a.)
line
5x − 4y = 6,
point
(−4, 3)

Answer by ikleyn(52867) About Me  (Show Source):
You can put this solution on YOUR website!
.
Any line perpendicular to the given line  5x - 4y = 6  has an equation


     5y + 4x = c,    (1)


where "c" is a constant term.


Since a line (1) should contain the point (-4,3), equation (1) must be true when you substitute
the coordinates of the point x= -4  and  y= 3 into the equation.


By doing it, you determine the value of "c" 


    5*3 + 4*(-4) = c = 15 - 16 = -1.


Therefore, your equation (1) takes the form


        5y + 4x = -1.


In the slope-intercept form, it is


         y = %28-4%2F5%29x+-+%281%2F5%29.


It is your final answer



    


    Plot y = 5x - 4y = 6 (red)  and  y = %28-4%2F5%29x+-+%281%2F5%29 (green)


Solved.

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