SOLUTION: In how many ways can four couples be seated in a row of eight seats at a theater if each couple is seated together?
Algebra ->
Permutations
-> SOLUTION: In how many ways can four couples be seated in a row of eight seats at a theater if each couple is seated together?
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ANSWER. = 1*2*3*4*16 = 384.
4! accounts for permutations of four couples considering each couple as one whole entity.
accounts for permutations inside each couple.
