SOLUTION: log3 (x+2) + log3 (x-2) = 1
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Question 113610
:
log3 (x+2) + log3 (x-2) = 1
Answer by
stanbon(75887)
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log3 (x+2) + log3 (x-2) = 1
log[(x+2)(x-2)] = 1
(x+2)(x-2) = 3^1
x^2-4 = 3
x^2-7 = 0
(x-sqrt7)(x+sqrt7) = 0
x = sqrt7 or x=-sqrt7
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Cheers,
Stan H.