SOLUTION: Find the standard form of the equation of the parabola with a focus at (7, 0) and a directrix at x = -7. choices below y = one divided by twenty eight x2 x = one divided

Algebra ->  Trigonometry-basics -> SOLUTION: Find the standard form of the equation of the parabola with a focus at (7, 0) and a directrix at x = -7. choices below y = one divided by twenty eight x2 x = one divided      Log On


   



Question 1135980: Find the standard form of the equation of the parabola with a focus at (7, 0) and a directrix at x = -7.
choices below

y = one divided by twenty eight x2

x = one divided by twenty eight y2

-28y = x2

y2 = 14x

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
given:
a focus at (7,+0) and a directrix at x+=+-7
since the vertex, exactly between the focus and directrix, must be at (h, k) = (0,+0)
the absolute value of p+is the distance between the vertex and the focus and the distance between the vertex and the directrix. (The sign on p tells me which way the parabola faces.) Since the focus and directrix are 7 units apart, then this distance has to be one unit, so abs%28p+%29+=7
Since this is a "sideway" parabola, then the y part gets squared, rather than the x part. So the conics form of the equation must be:
%28y-+y%5B1%5D%29%5E2+=+4p%28x+-x%5B1%5D%29...plug in p+=7 and coordinates of the vertex (0,+0)
%28y-+0%29%5E2+=+4%287%29%28x+-0%29
y%5E2+=+28x+
x=%281%2F28%29y%5E2+=> your answer