SOLUTION: A baseball is hit 2 feet above the ground with an initial upward velocity of 48 feet per second.The height of the baseball is given by the equation s(t)=-16t^2+48t+2 where the heig
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-> SOLUTION: A baseball is hit 2 feet above the ground with an initial upward velocity of 48 feet per second.The height of the baseball is given by the equation s(t)=-16t^2+48t+2 where the heig
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Question 1135969: A baseball is hit 2 feet above the ground with an initial upward velocity of 48 feet per second.The height of the baseball is given by the equation s(t)=-16t^2+48t+2 where the heigth, s(t), is in feet and the time t is in seconds. A) At what time does the ball reach its maximum heigth?.B)What is the maximum heigth of the ball? C)When does the ball hit the ground for the first time? D) use A),B),C) to graph parabola. Answer by ikleyn(52921) (Show Source):
