SOLUTION: what is the smallest positive integer of k such that the equation sqrt(x - 127) + sqrt(k - x) = 13 has at least one real solution for x?

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Question 1135942: what is the smallest positive integer of k such that the equation sqrt(x - 127) + sqrt(k - x) = 13 has at least one real solution for x?
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%28x+-+127%29+%2B+sqrt%28k+-+x%29+=+13

Isolate a square root term:

sqrt%28x+-+127%29+=+13+-+sqrt%28k+-+x%29

Square both sides:

x+-+127+=+%2813+-+sqrt%28k+-+x%29%29%5E2

x+-+127+=+%2813+-+sqrt%28k+-+x%29%29%2813+-+sqrt%28k+-+x%29%29

x+-+127+=+169-26sqrt%28k-x%29%2B%28k-x%29

Add 127 to both sides

x+=+296-26sqrt%28k-x%29%2Bk-x

Add x to both sides:

2x+=+296-26sqrt%28k-x%29%2Bk

Isolate the square root term

26sqrt%28k-x%29=+296-2x%2Bk

Square both sides:

676%28k-x%29=+%28296-2x%2Bk%29%5E2

676k-676x+=+87616+%2B+4x%5E2+%2B+k%5E2+-+1184x+%2B+592k+-+4kx

-4x%5E2-676x+%2B+1184x+%2B+4kx+-+87616+-+k%5E2+-+592k+%2B+676k+=+0

-4x%5E2%2B508x+%2B+4kx+-+87616+-+k%5E2+%2B+84k+=+0

Change all signs

4x%5E2-508x+-+4kx+%2B+87616+%2B+k%5E2+-+84k+=+0

4x%5E2%2B%28-508+-+4k%29x+%2B+k%5E2+-+84k+%2B+87616+=+0

4x%5E2%2B%28-508+-+4k%29x+%2B+%28k%5E2+-+84k+%2B+87616%29+=+0

This quadratic will have a real solution if and only if
its discriminant is not negative:

Discriminant = B²-4AC =

%28-508+-+4k%29%5E2-4%284%29%28k%5E2+-+84k+%2B+87616%29

%28-508+-+4k%29%28-508-4k%29-16%28k%5E2+-+84k+%2B+87616%29

258064+%2B+4064k+%2B+16k%5E2+-16k%5E2+%2B+1344k-1401856

5408k-1143792

2704%282k+-+423%29

This discriminant will be nonnegative if

2k-423%3E=0

2k%3E=423

k%3E=211.5

So the answer is the next integer after 211.5 which is 212.

Edwin