SOLUTION: Two cars start from towns 540 mi apart and travel toward each other. They meet after 6 hr. Find the speed of each car if one travels 10 mph faster than the other.

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Question 1135801: Two cars start from towns 540 mi apart and travel toward each other. They meet after 6 hr. Find the speed of each car if one travels 10 mph faster than the other.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39623) About Me  (Show Source):
Answer by ikleyn(52834) About Me  (Show Source):
You can put this solution on YOUR website!
.

            Ignore post by @josgarithmetic, since it is totally wrong  (giving the answer of  45  mph for the slower car).

            The correct solution is below: 


Let "r" be the speed of the slower car. Then


    6r + 6*(r+10) = 540     <<<---===  the sum of the two distances


    6r + 6r + 60 = 540

    12r = 540-60

     r =  480/12 = 40.


ANSWER.  The slower car speed is 40 mph;  the faster car speed is 50 mph.

Solved.

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