SOLUTION: A submarine left Hawaii travelling west four hours before an aircraft carrier. The aircraft carrier traveled in the opposite direction going 8 mph slower than the submarine for thr

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Question 1135794: A submarine left Hawaii travelling west four hours before an aircraft carrier. The aircraft carrier traveled in the opposite direction going 8 mph slower than the submarine for three hours which time the ships were 206 miles apart. Find the submarine's speed.
Answer by ikleyn(52790) About Me  (Show Source):
You can put this solution on YOUR website!
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4x + 3*(x + (x-8)) = 206       <<<---===  the sum of the two distances


4x + 3x + 3x - 24 = 206


10x = 206 + 24


10x = 230


x = 230/10 = 23 miles per hour is the submarine' speed.     ANSWER