SOLUTION: The product of three consecutive integers is 21 more than the cube of the smallest integer. The smallest integer is -3 -4 -5 -6

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: The product of three consecutive integers is 21 more than the cube of the smallest integer. The smallest integer is -3 -4 -5 -6      Log On


   

Question 1135751: The product of three consecutive integers is 21 more than the cube of the smallest integer. The smallest integer is
-3
-4
-5
-6
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

The formulation is:
+x%28x%2B1%29%28x%2B2%29+=+x%5E3%2B21+
+x%5E3%2B3x%5E2%2B2x+=+x%5E3%2B21+
++3x%5E2%2B2x-21+=+0+
+%283x-7%29%28x%2B3%29+=+0+
x = -3 and x = 7/3 are solutions to this equation, but only
+highlight%28+x+=+-3+%29+ is an integer solution

Checked by plugging in x=-3.