Question 1135746: Jake's water bill is $30.10 per month plus $2.30 per ccf (hundred cubic feet) of water. What is the maximum number of ccf Jake can use if he wants his bill to be no more than $60?
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! the water bill is 30.10 per month plus 2.30 per ccf (hundred cubic feet) of waer.
you want the bill to be less than or equal to 60 dollars.
cost equation is:
c = 30.10 + 2.30 * x
c is the total cost.
x is the number of ccf.
if jake wants c to be less than or equal to 60 dollars, then the formula for that is c <= 60
since c = 30.10 + 2.30 * x, the formula becomes 30.10 + 2.30 * x <= 60 dollars
subtract 30.10 from both sides of this equation to get 2.30 * x <= 60 - 30.10.
combine like terms to get 2.30 * x <= 29.90.
divide both sides of this inequality by 2.30 to get x <= 29.90 / 2.30
solve for x to get x = 13.
to keep the total bill less than or equal to 60 dollars, jake must keep his ccf less than or equal to 13.
when x = 13, the formula of c = 30.10 + 2.30 * x becomes c = 30.10 + 2.30 * 13 which becomes c = 30.10 + 29.9 which becomes c = 60.
if x is less than 13, the total bill will be less than 60 dollars.
if x is greater than 13, the total bill will be greater than 60 dollars.
the maximum ccf it can be is therefore 13 if jake wants to keep the bill a maximum of 60 dollars for the month.
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