SOLUTION: Can someone help me with this? I am really confused with the answers I keep coming up with. If y= (sqrt of x) - 2, fill in the following table for x = 0, 1, 2, 3, 4. Round to th

Algebra ->  Functions -> SOLUTION: Can someone help me with this? I am really confused with the answers I keep coming up with. If y= (sqrt of x) - 2, fill in the following table for x = 0, 1, 2, 3, 4. Round to th      Log On


   



Question 113574: Can someone help me with this? I am really confused with the answers I keep coming up with.
If y= (sqrt of x) - 2, fill in the following table for x = 0, 1, 2, 3, 4. Round to three decimal places where necessary.
Thank you in adveance for your help.

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
y=sqrtx-2
y=sqrt0-2
y=-2 answer.
y=sqrt1-2
y=1-2
y=-1 answer.
y=sqrt2-2
y=1.414-2
y=.586 answer.
y=sqrt3-2
y=1.732-2
y=-.268 answer
y=sqrt4-2
y=2-2
y=0 answer.