Question 113571: Find the length and width of a rectangle whose perimeter is 40 feet, and whose area is 96 square feet.
I think I have the right equation for the perimeter: P=2l+2w=96 sq ft.
Is this right?
I do not know how to set the other equation up or solve it.
thanks
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the length and width of a rectangle whose perimeter is 40 feet, and whose area is 96 square feet.
I think I have the right equation for the perimeter: P=2l+2w=40 ft.
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Then, divide thru by 2 to get:
l + w = 20
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If width = w, length = 20-w
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AREA:
Area = (length)(width)
96 = w(20-w)
96 = 20w-w^2
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w^2 -20w+96 = 0
(w-8)(w-12)=0
If w=8 then length = 12
If w=12 then length = 8
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Cheers,
Stan H.
I do not know how to set the other equation up or solve it.
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