SOLUTION: Using the vertex (h,k) and a point on the graph (x,y), how do I find the general equation from of: (h,k)= (2,0), (x,y)= (4,4) ?

Algebra ->  Rational-functions -> SOLUTION: Using the vertex (h,k) and a point on the graph (x,y), how do I find the general equation from of: (h,k)= (2,0), (x,y)= (4,4) ?      Log On


   

Question 1135704: Using the vertex (h,k) and a point on the graph (x,y), how do I find the general equation from of:
(h,k)= (2,0), (x,y)= (4,4) ?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

the quadratic is written in the form y+=+a%28x++-++h%29%5E2+%2B+k, where the vertex is the point (h, k)
given:
(h, k)
= (2, 0)
and (x, y)=(4, 4)
using vertex, you have
y+=+a%28x++-++2%29%5E2+%2B+0
y+=+a%28x++-++2%29%5E2+

now use given point and calculate a
4=+a%284++-++2%29%5E2
4=+a%282%29%5E2+
4=+4a+
a=1

so your equation is: y+=+1%28x++-++2%29%5E2+=>y+=+%28x++-++2%29%5E2+