SOLUTION: In Triangle ABC B=5 C=4 the area of the triangle is 15√7 divided by 4. To the nearest tenth calculate A and measure of angle a (in degrees) thank you in advance for helping me ou

Algebra ->  Trigonometry-basics -> SOLUTION: In Triangle ABC B=5 C=4 the area of the triangle is 15√7 divided by 4. To the nearest tenth calculate A and measure of angle a (in degrees) thank you in advance for helping me ou      Log On


   



Question 1135700: In Triangle ABC B=5 C=4 the area of the triangle is 15√7 divided by 4. To the nearest tenth calculate A and measure of angle a (in degrees) thank you in advance for helping me out
Answer by ikleyn(52915) About Me  (Show Source):
You can put this solution on YOUR website!
.

I answered this question and solved this problem under this link

https://www.algebra.com/algebra/homework/Trigonometry-basics/Trigonometry-basics.faq.question.1135553.html

https://www.algebra.com/algebra/homework/Trigonometry-basics/Trigonometry-basics.faq.question.1135553.html


It is the only one true, fully completed and correct solution among the three solution in that post.

For your convenience, I copy and paste it here one more time, rounding answer to nearest tenth.


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For any triangle, its area is half the product of the lengths of any its two sides and the sine of the angle between them.


In your case, the Area = %281%2F2%29%2Ab%2Ac%2Asin%28A%29.


Substituting your data, you have %2815%2Asqrt%287%29%29%2F4 = %281%2F2%29%2A5%2A4%2Asin%28A%29.


From here,  sin(A) = %282%2A15%2Asqrt%287%29%29%2F%284%2A5%2A4%29 = 0.992167.


Then  for angle A you have TWO possible values  m ( < A ) = 82.9°  and  m ( < A) = 180° - 82.9° = 97.1°.    ANSWER 

Solved.


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