SOLUTION: How many seven-letter code words can be formed using a standard 26 alphabet if repetition is allowed? And if repetition is not allowed?

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: How many seven-letter code words can be formed using a standard 26 alphabet if repetition is allowed? And if repetition is not allowed?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1135577: How many seven-letter code words can be formed using a standard 26 alphabet if repetition is allowed? And if repetition is not allowed?
Answer by ikleyn(52805) About Me  (Show Source):
You can put this solution on YOUR website!
.

There are 26 independent opportunities for each of the 7 positions,


so the total number of 7-letter codes is  26%5E7 = 8031810176.   ANSWER

Solved.