Question 1135486: A ballet company sells 540 tickets for its upcoming performance of Swan Lake. Tickets for the orchestra center and front balcony seats are $56. Tickets for the left and right orchestra and balcony seats are $38. The company has sold $24,120 in tickets. How many $56 and $38 seats were sold?
Found 2 solutions by Shin123, MathTherapy: Answer by Shin123(626) (Show Source): Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website! A ballet company sells 540 tickets for its upcoming performance of Swan Lake. Tickets for the orchestra center and front balcony seats are $56. Tickets for the left and right orchestra and balcony seats are $38. The company has sold $24,120 in tickets. How many $56 and $38 seats were sold?
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Let the number of $56 tickets sold be F, and the number of $38 tickets, T
We then get: F + T = 540 ------- eq (i)
Also, 56F + 38T = 24,120 ------- eq (ii)
- 38F - 38T = - 20,520 --------- Multiplying eq (i) by - 38 ------ eq (iii)
18F = 3,600 ------ Adding eqs (iii) & (ii)
F, or number of $56 tickets sold = 
Substitute 200 for F in eq (i) to get the value of T, the number of $38 tickets sold.
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