SOLUTION: 13. (18 pts) The cost, in dollars, for a company to produce x widgets is given by C(x) = 4050 + 9.00x for x ≥  0, and the price-demand function, in dollars per widget, is

Algebra ->  Equations -> SOLUTION: 13. (18 pts) The cost, in dollars, for a company to produce x widgets is given by C(x) = 4050 + 9.00x for x ≥  0, and the price-demand function, in dollars per widget, is      Log On


   



Question 1135433: 13. (18 pts) The cost, in dollars, for a company to produce x widgets is given by
C(x) = 4050 + 9.00x for x ≥  0, and the price-demand function, in dollars per widget, is p(x) = 63-0.03x for 0 ≤ x ≤ 2100.
In Quiz 2, problem #10, it was seen that the profit function for this scenario isP(x) = -0.03x^2 + 54.00x-4050.
(a) The profit function is a quadratic function and so its graph is a parabola. Does the parabola open up or down? __________
(b) Find the vertex of the profit function P(x) using algebra. Show algebraic work.
(c) State the maximum profit and the number of widgets which yield that maximum profit:
The maximum profit is _____________, when ___________ widgets are produced and sold. (d) Determine the price to charge per widget in order to maximize profit.
(e) Find and interpret the break-even points. Show algebraic work.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

The cost, in dollars, for a company to produce x widgets is given by
C%28x%29+=+4050+%2B+9.00x for x+%3E=++0, and
the price-demand function, in dollars per widget, is

p%28x%29+=+63-0.03x for+0+%3C=+x+%3C=2100
In Quiz 2, problem #10, it was seen that the profit function for this scenario is
P%28x%29+=+-0.03x%5E2+%2B+54.00x-4050
(a) The profit function is a quadratic function and so its graph is a parabola. Does the parabola open up or down? ___down_______
(b) Find the vertex of the profit function P(x) using algebra.
P%28x%29+=+-0.03%28x%5E2+-54.00x%2F0.03%29-4050
P%28x%29+=+-0.03%28x%5E2+-1800x%29-4050...complete square
P%28x%29+=+-0.03%28x%5E2+-1800x%2Bb%5E2%29-%28-%280.03%29%28b%5E2%29%29-4050
recall: 2ab=1800
since a=1, we have 2b=1800...solve for b
b=900

then we have
P%28x%29+=++-+0.03+%28x%5E2+-1800x%2B900%5E2%29-%28-%280.03%29%28900%5E2%29%29-4050
P%28x%29+=++-+0.03+%28x+-900%29%5E2%29%2B24300-4050
P%28x%29+=++-+0.03+%28x+-+900%29%5E2%2B20250
=>h=900 and k=20250
vertex is at: (900,20250)

(c) State the maximum profit and the number of widgets which yield that maximum profit:
The maximum profit is _____20250 ________, when ___x=900________ widgets are produced and sold.
(d) Determine the price to charge per widget in order to maximize profit.
p%28x%29+=+63-0.03x...plug in x=900
p%28x%29+=+63-0.03%2A900
p%28x%29+=+63-27
p%28x%29+=+36

(e) Find and interpret the break-even points. Show algebraic work.
Break-Even _Point => when C%28x%29+=P%28x%29
if
C%28x%29+=+4050+%2B+9.00x
P%28x%29+=+-0.03x%5E2+%2B+54.00x-4050
then 4050+%2B+9.00x=-0.03x%5E2+%2B+54.00x-4050
4050+%2B+9.00x%2B0.03x%5E2+-+54.00x%2B4050=0
0.03+x%5E2+-+45+x+%2B+8100+=+0+...using quadratic formula we get:
x209.167
x1290.83