SOLUTION: The sum of three numbers in G.P is 21 and the sum of their squares is 189.Find the numbers

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Question 1135338: The sum of three numbers in G.P is 21 and the sum of their squares is 189.Find the numbers

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

In General we write a Geometric Sequence like this:
{ a, ar, ar%5E2, ar%5E3, ... } where:

a is the first term, and
r is the factor between the terms (called the "common ratio")

if the sum of three numbers in G.P is 21, we have

a%2Bar%2Bar%5E2=21....solve for a
a%281%2Br%2Br%5E2%29=21
a=21%2F%281%2Br%2Br%5E2%29.....eq.1


and, if the sum of their squares is 189, we have

a%5E2%2B%28ar%29%5E2%2B%28ar%5E2%29%5E2=189...solve for a
a%5E2%2Ba%5E2+r%5E2%2Ba%5E2r%5E4=189
a%5E2%281%2Br%5E2%2Br%5E4%29=189
a%5E2=189%2F%281%2Br%5E2%2Br%5E4%29
a=sqrt%28189%2F%281%2Br%5E2%2Br%5E4%29%29........eq.2

from eq.1 and eq.2 we have

21%2F%281%2Br%2Br%5E2%29=sqrt%28189%2F%281%2Br%5E2%2Br%5E4%29%29........square both sides
441%2F%281%2Br%2Br%5E2%29%5E2=189%2F%281%2Br%5E2%2Br%5E4%29
441%281%2Br%5E2%2Br%5E4%29=189%281%2Br%2Br%5E2%29%5E2
441%281%2Br%5E2%2Br%5E4%29=189%28r%5E4+%2B+2+r%5E3+%2B+3+r%5E2+%2B+2+r+%2B+1%29
441%2B441r%5E2%2B441r%5E4=189+r%5E4+%2B+378+r%5E3+%2B+567+r%5E2+%2B+378+r+%2B+189
441%2B441r%5E2%2B441r%5E4-189+r%5E4+-+378+r%5E3+-+567+r%5E2+-+378+r+-+189=0
252+r%5E4+-+378+r%5E3+-+126+r%5E2+-+378+r+%2B+252=0.........factor
126+%282+r+-+1%29+%28r+-+2%29+%28r%5E2+%2B+r+%2B+1%29=0
solutions:
if 2r-1=0=>r=1%2F2
if r-2=0=>r=2
if %28r%5E2+%2B+r+%2B+1%29=0=> use quadratic formula and you will get complex solutions
r+=+-%28-1%29%5E%281%2F3%29->disregard

now find a:
a=21%2F%281%2Br%2Br%5E2%29.....eq.1, plug in r=1%2F2
a=21%2F%281%2B1%2F2%2B%281%2F2%29%5E2%29
a=21%2F%281%2B1%2F2%2B1%2F4%29
a=21%2F%284%2F4%2B2%2F4%2B1%2F4%29
a=21%2F%287%2F4%29
a=%2821%2A4%29%2F7
a=3%2A4
a=12

or
a=21%2F%281%2Br%2Br%5E2%29.....eq.1, plug in r=2
a=21%2F%281%2B2%2B2%5E2%29
a=21%2F7
a=3

then a, ar, ar%5E2 will be
if a=12 and r=1%2F2
a=12
ar=12%2A%281%2F2%29=6
ar%5E2=12%2A%281%2F4%29=3

or
if a=3 and r=2
a=3
ar=3%2A2=6
ar%5E2=3%2A4=12
you actually got same terms in reverse order

check their sum:
12%2B6%2B3=21 and
12%5E2%2B6%5E2%2B3%5E2=189
144%2B36%2B9=189
189=189