SOLUTION: a truck enters the highway driving 60 miles per hour . a car enters the highway the same place 8 minutes later and drives 68miles per hour in the same direction . from the time the

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Question 1135327: a truck enters the highway driving 60 miles per hour . a car enters the highway the same place 8 minutes later and drives 68miles per hour in the same direction . from the time the car enters the highway how minutes will it take the car to pass the truck
Found 4 solutions by josgarithmetic, greenestamps, ikleyn, MathTherapy:
Answer by josgarithmetic(39620)   (Show Source):
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The car will close a distance of 8 miles.

For time x in hours,

~~About 1 hour 7.5 minutes~~

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Steps should be:

,

Answer by greenestamps(13200)   (Show Source):
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60 miles an hour is 1 mile a minute, so when the car enters the highway the truck is 8 miles ahead.

The difference in the speeds of the two vehicles is 8 miles per hour; so in exactly 1 hour the car will make up those 8 miles and catch up to the truck.

Answer by ikleyn(52803)   (Show Source):
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.

            The post by @josgarithmetic is, OBVIOUSLY, incorrect.

            The corrected version is below:

When the car enters on the highway 8 minutes later, the track is exactly 8 miles ahead the car. Starting from this time moment, the distance between them decreases at the rate (68-60) = 8 miles per hour. So, to find the time "t", when catching will happen, you simply need to solve an equation (68-60)*t = 8 miles (8 miles is the "head start" in this case) 8t = 8, giving the ANSWER t = = 1 hour.

Solved.

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Answer by MathTherapy(10553)   (Show Source):
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a truck enters the highway driving 60 miles per hour . a car enters the highway the same place 8 minutes later and drives 68miles per hour in the same direction . from the time the car enters the highway how minutes will it take the car to pass the truck

Let time it’ll take the car to catch up to the truck, be T
Then we get the following DISTANCE equation:
68T = 60T + 8
68T - 60T = 8
8T = 8
T, or time it'll take car: