Question 1135239: In a game, the player and the house each roll a die.
Whoever gets the higher number wins.
Player and House each roll a die, higher number wins.
In ties, Player rolls again, but must roll higher than the tie number (no more rerolls on ties)
What are all the possible events for this game? and how would I calculate the expected value of the game to the house and player?
Answer by its.evapatel(3)   (Show Source):
You can put this solution on YOUR website! You would use combinations for this problem. You can easily multiply 6 and 2. 6 ( 6 sides on a die),2 (2 people). Which are 12 combinations.
1,a
2,a
3,a
4,a
5,a
6,a
1,b
2,b
3,b
4,b
5,b
6,b
The highest number on the die is 6 and there are two possibilities out of twelve. Which is 1/6.
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