Question 113521: Find the equation, in standard form, with all integer coefficients, of the line perpendicular to 3x-6y=9 and passing through (-2,-1)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the equation, in standard form, with all integer coefficients, of the line perpendicular to 3x-6y=9 and passing through (-2,-1)
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The given line can be written as y = (1/2)(x)-(3/2)
It has slope = (1/2)
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Any line perpendicular to it has slope -2
The line you want has form y = mx + b
Substitute to solve for "b":
-1 = -2*-2+b
-1 = 4+b
b = -5
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EQUATION:
y = -2x -5 is perpendicular to 3x-6y=9 and passes thru (-2,-1)
It's studard form is 2x+y+5=0
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Cheers,
Stan H.
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