SOLUTION: The Little League concession stand sells candy bars for 35 cents and water for 20 cents. On a hot day, they sell 5 times as much water as they do candy. When receipts are $ 16.20 f
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Question 1135171: The Little League concession stand sells candy bars for 35 cents and water for 20 cents. On a hot day, they sell 5 times as much water as they do candy. When receipts are $ 16.20 find how many of each type they sell. Found 3 solutions by josgarithmetic, ikleyn, greenestamps:Answer by josgarithmetic(39621) (Show Source):
Let x be the number of candy bars;
then the number of water cans/(cups)/(containers) is 5x
The "money" equation is
35x + 20*(5x) = 1620 cents
Simplify and solve
35x + 100x = 1620
135x = 1620 ============> x = = 12.
ANSWER. 12 candy bars and 12*5 = 60 water cans/(cups)/(containers).
CHECK. 12*35 + 60*20 = 1620 cents = $16.20. ! Correct !
Solved.
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If it is true that the solution must be as simple as possible (as it is usually expected and is commonly accepted), then
this problem is to be solved using one equation for one single unknown.
I absolutely concur with the statement that this problem is suited for being solved with one unknown. Using two variables and then using substitution is a big waste of effort.
If the number of candies sold is x, the number of waters sold is 5x.
Then one way you can make the numbers in the problem smaller is to imagine the candies and waters being sold in equal groups, each with 5 waters and 1 candy. The cost of one of those groups is 5 times 20 cents plus 1 times 35 cents, or $1.35. Then do some mental or pencil-and-paper calculations to see how many of those groups it takes to make the total sales of $16.20.
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