SOLUTION: I tried dividing by nine on both sides and it got me to 4x^2 - 2x - 13/2 = 0. But I don't know what to do next.
Find the dimensions: *triangle* base of (2x+1) and height of (2x-
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-> SOLUTION: I tried dividing by nine on both sides and it got me to 4x^2 - 2x - 13/2 = 0. But I don't know what to do next.
Find the dimensions: *triangle* base of (2x+1) and height of (2x-
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Question 1135155: I tried dividing by nine on both sides and it got me to 4x^2 - 2x - 13/2 = 0. But I don't know what to do next.
Find the dimensions: *triangle* base of (2x+1) and height of (2x-2)
Please help.
Thanks in advance. Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! -----
I tried dividing by nine on both sides and it got me to 4x^2 - 2x - 13/2 = 0. But I don't know what to do next.
Find the dimensions: *triangle* base of (2x+1) and height of (2x-2)
Please help.
Thanks in advance.
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Why the 9? Where did that come from? Was 9 the value for the area?
If area is 9, then
Can you finish from here? Either try factorizing or use general solution of quadratic equation.