SOLUTION: Find an equation of the line through the given points. Write the equation in standard form. Through (6,2) and (8,8).

Algebra ->  Equations -> SOLUTION: Find an equation of the line through the given points. Write the equation in standard form. Through (6,2) and (8,8).       Log On


   



Question 113515: Find an equation of the line through the given points. Write the equation in standard form.
Through (6,2) and (8,8).

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
First lets find the slope through the points (6,2) and (8,8)

m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula (note: is the first point (6,2) and is the second point (8,8))

m=%288-2%29%2F%288-6%29 Plug in y%5B2%5D=8,y%5B1%5D=2,x%5B2%5D=8,x%5B1%5D=6 (these are the coordinates of given points)

m=+6%2F2 Subtract the terms in the numerator 8-2 to get 6. Subtract the terms in the denominator 8-6 to get 2


m=3 Reduce

So the slope is
m=3

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Now let's use the point-slope formula to find the equation of the line:



------Point-Slope Formula------
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is one of the given points

So lets use the Point-Slope Formula to find the equation of the line

y-2=%283%29%28x-6%29 Plug in m=3, x%5B1%5D=6, and y%5B1%5D=2 (these values are given)


y-2=3x%2B%283%29%28-6%29 Distribute 3

y-2=3x-18 Multiply 3 and -6 to get -18

y=3x-18%2B2 Add 2 to both sides to isolate y

y=3x-16 Combine like terms -18 and 2 to get -16
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Answer:


So the equation of the line which goes through the points (6,2) and (8,8) is:y=3x-16

The equation is now in y=mx%2Bb form (which is slope-intercept form) where the slope is m=3 and the y-intercept is b=-16

Notice if we graph the equation y=3x-16 and plot the points (6,2) and (8,8), we get this: (note: if you need help with graphing, check out this solver)

Graph of y=3x-16 through the points (6,2) and (8,8)

Notice how the two points lie on the line. This graphically verifies our answer.


However, the problem wants the answer in standard form. So let's convert the equation into standard form.

Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)
Convert from slope-intercept form (y = mx+b) to standard form (Ax+By = C)


y+=+3x-16 Start with the given equation


1y-3x+=+3x-16-3x Subtract 3x from both sides


-3x%2B1y+=+-16 Simplify


-1%2A%28-3x%2B1y%29+=+-1%2A%28-16%29 Multiply both sides by -1 to make the A coefficient positive (note: this step may be optional; it will depend on your teacher and/or textbook)


3x-1y+=+16 Distribute and simplify


The original equation y+=+3x-16 (slope-intercept form) is equivalent to 3x-1y+=+16 (standard form where A > 0)


The equation 3x-1y+=+16 is in the form Ax%2BBy+=+C where A+=+3, B+=+-1 and C+=+16