SOLUTION: I will link the image at the bottom because I couldn’t write it in the question. This question talks about how the sqrt of x is to the exponent of sqrt of x indefinitely. The a

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: I will link the image at the bottom because I couldn’t write it in the question. This question talks about how the sqrt of x is to the exponent of sqrt of x indefinitely. The a      Log On


   



Question 1134770: I will link the image at the bottom because I couldn’t write it in the question.
This question talks about how the sqrt of x is to the exponent of sqrt of x indefinitely. The answer to it is 2 but the goal is to find x. How would you solve this question?
Image : https://ibb.co/pdHnWmt

Answer by greenestamps(13209) About Me  (Show Source):
You can put this solution on YOUR website!


Given: sqrt(x)^sqrt(x)^sqrt(x)^sqrt(x)^sqrt(x)^sqrt(x)... = 2

Square both sides, remembering that %28a%5Eb%29%5E2+=+a%5E%282b%29

sqrt(x)^(2*sqrt(x)^sqrt(x)^sqrt(x)^sqrt(x)...) = 4

sqrt(x)^(2*2) = 4 [everything after the 2 in that equation is equal to what we started with; its value is 2]

sqrt(x)^4 = 4

x^2 = 4

x = 2

The result can be verified using excel, or a graphing calculator.

(1) Calculate the square root of 2;
(2) calculate the square root of 2 raised to that power;
repeat step (2) repeatedly