SOLUTION: The Mean weight of 500 male students at VIT University is 151 lb and the standard deviation is 151 1b. Assuming that the weights are normally distributed, find how many students we
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-> SOLUTION: The Mean weight of 500 male students at VIT University is 151 lb and the standard deviation is 151 1b. Assuming that the weights are normally distributed, find how many students we
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Question 1134545: The Mean weight of 500 male students at VIT University is 151 lb and the standard deviation is 151 1b. Assuming that the weights are normally distributed, find how many students weight (a) between 120 and 155 1b, (b) more than 185 lb. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! z=(x-mean)/sd
for 120 z is (120-151)/151 or -0.205
for 155, it is 4/151 or +0.03
probability of z between those two is 0.0932 That times 500 is 46.6, so 47
>185 is z>(34/151) or +0.225
z>0.225 has probability of 0.4110, which would be 205.49 or 205 students
