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Question 1134443: Solve the linear programming problem. Show the Graph. Maximize C = -3x + 5y subject to:
x-y>=-3
2x+y<=12
x>=0
y>=0
Maximum:
Answer by mathsolverplus(88)   (Show Source):
You can put this solution on YOUR website! Under the given conditions, the overlapping area is a quadrilateral with four
vertices: (0,0) (0,3) (3,6) and (6,0)
Substitute each into the C=-3x+5y to see which one gives the highest value.
If (0,0):
C=0
If (0,3):
C = 0 + 5(3) = 15
If (3,6):
C = -3(3)+5(6) = -9+30 = 21
If (6,0):
C = -3(6) + 5(0) = -18
Maximum occurs at C=21 when x = 3 and y = 6.
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