Question 1134438: Kendra has $2.75 in dimes and nickels. If she has twice as many as nickels, how many of each coin does she have? Found 2 solutions by mathsolverplus, ikleyn:Answer by mathsolverplus(88) (Show Source):
You can put this solution on YOUR website! We will set up two equations with two unknowns here.
Let dime = d, which is worth $0.1 each
Let nickels = n, which is worth $0.05 each
$0.1d + $0.05n = $2.75 - equation (1)
d = 2n - equation (2)
Substitute d = 2n into the first equation:
$0.1(2n) + $0.05n = $2.75
$0.2n + $0.05n = $2.75
$0.25n = $2.75
n = 11
d = 2n = 22
She has 11 nickels and 22 dimes.
For more additional instant FREE math help, please check out and follow us on social media!!
Instagram (@mathsolver.plus) : https://www.instagram.com/mathsolver.plus/
Twitter (@MathSolverPlus): https://twitter.com/MathSolverPlus
Snapchat (@mathsolverplus)
Email: mathsolverplus@gmail.com
You can put this solution on YOUR website! .
Kendra has $2.75 in dimes and nickels. If she has twice as many as nickels, how many of each coin does she have?
~~~~~~~~~~~~~~~~~~~~
Please pay attention on how I edited your post in order for it makes sense.
Solution
Kendra is VERY SMART. She prefers to solve the problem MENTALLY, instead of using equations - when and where it is reasonable . . .
Therefore, she groups ( ! MENTALLY ! ) her coins in sets, each containing (1 nickel and 2 dimes).
According to the condition, she can do it (!)
Then each group is worth 2*10+5 = 25 cents; hence, the number of groups is = 11.
Therefore, the ANSWER is: there are 11 nickels and 22 dimes in Kendra's collection.
You will find there the lessons for all levels - from introductory to advanced,
and for all methods used - from one equation to two equations and even without equations.
Read them attentively and become an expert in this field.
