SOLUTION: Write the equation of the line passing through (2, -1) and (3, -1). Thank you for the help.

Algebra ->  Linear-equations -> SOLUTION: Write the equation of the line passing through (2, -1) and (3, -1). Thank you for the help.      Log On


   

Question 113428This question is from textbook Beginning Algebra
: Write the equation of the line passing through (2, -1) and (3, -1).
Thank you for the help. This question is from textbook Beginning Algebra

Found 2 solutions by scott8148, MathLover1:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the x value changes but the y value doesn't, so slope is zero and y is -1

y=-1

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

here are details:
Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (2, -1) and (x2, y2) = (3, -1).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%28-1--1%29%2F%283-2%29+=+0.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 0%2A2+%2Bb+=+-1. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=-1-0%2A2+=+-1.

y=(0)x + (-1)

Your graph: