SOLUTION: Write the complex number in the form a + bi. 4[cos (-135°) + i sin (-135°)] Which answer is it, these are the choices for the problem below. A.negative two square root tw

Algebra ->  Trigonometry-basics -> SOLUTION: Write the complex number in the form a + bi. 4[cos (-135°) + i sin (-135°)] Which answer is it, these are the choices for the problem below. A.negative two square root tw      Log On


   

Question 1134132: Write the complex number in the form a + bi.
4[cos (-135°) + i sin (-135°)] Which answer is it, these are the choices for the problem below.

A.negative two square root two plus two square root two i

B.negative two square root two minus two square root two i

C.negative square root two minus square root two i

D.negative square root two plus square root two i
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
cos (-135) is -sqrt(2)/2 and sin (-135) is - sqrt(2)/2
-2 sqrt(2)-2i sqrt(2)
this is -2 sqrt(2)-2 sqrt(2)*i B
it can also be written as -2sqrt(2)[1+i]