Question 1134131: A telephone company offers customers two payment plans for monthly service.
Plan A costs $5 per month plus $0.10 per minute for calls.
Plan B costs $8 per month plus $0.07 per minute for calls.
a) how many minutes of calls would it take for plan A and PLan B to cost the same? Use mathematics to explain how you determined your answer. Use words, symbols, or both in your explanation.
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! let x be the total number of minutes of calls in a month
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Let C(A) be the cost of plan A and C(B) be the cost of plan B
:
C(A) = 5 +0.10x
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C(B) = 8 +0.07x
:
For this problem, we want C(A) = C(B)
:
5 +0.10x = 8 +0.07x
:
0.03x = 3
:
x = 3/0.03 = 100
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100 minutes of calls in a month results in C(A) = C(B)
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check the answer
:
C(A) = 5 +0.10 * 100 = $15
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C(B) = 8 +0.07 * 100 = $15
:
C(A) = C(B) for 100 minutes in a month
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