SOLUTION: A team of four members consisting of eight mathematicians and seven chemists will be selected. Calculate the number of different ways to form a team member if all members are mathe

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Question 1134100: A team of four members consisting of eight mathematicians and seven chemists will be selected. Calculate the number of different ways to form a team member if all members are mathematicians? if the number of mathematicians and chemists are equal? if the team contains at least two mathematicians?
Answer by Boreal(15235) About Me  (Show Source):
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15 total
for four mathematicians only
8/15*7/14*6/13*5/12=0.0513
equal would be 2 of each
total number of ways to choose any four is 15C4=1365
for the numerator 8C2*7C2=28*21=588
the probability is 588/1365=0.4307
At least two mathematicians
for 3 would be 8C3*7C1=56*7=392, and that probability is 0.2872
for 4, 0.0513
So at least two would be the sum of three terms or 0.7692